Tuesday 9 October 2012

Preparing for Halloween

On Friday October 27th Mrs. Barker will be taking her children to a Halloween Party.   She has offered to purchase the candy for the pinata.    There will be 30 children at the party.   Mrs. Barker went to London Drugs to buy the candy and noticed each bag of candy has 35 pieces.   How many bags will Mrs. Barker need to purchase so that every child at the party gets between 10 and 12 pieces of candy?  

Don't forget to share how you got your answer...

11 comments:

  1. First i did 30x10 which is 300 because there is 30 children and each children wants 10 candies so i did 300 divided by 35 and its 8.5 so 9 is the answer.

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  2. I think you need to have 10 bags of candies because 35 pieces of candies times 10 =350 and so all the children get 11 pieces and there are 20 remainders.



    By :QL

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  3. you need 9 bags. Because nine times thirty fives is 315. Remainder is 15 Mrs.Robson can eat it.

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  4. the answer is 9 bags because 35+35+35+35+35+35+35+35+35=315 and 15 remainder .We need three hundred candies.

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  5. The awnser is 315 candies.And 15 remander.So Mrs.Barker will have to buy 9 bags.


    I jest LOVE halloween!


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  6. Mrs Barker need to have 10bags of candy but there are too many ,so Mrs Barker will eat 20 candys:
    11 times 30=330
    35 times 10=350
    350-330=20

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  7. 11x30=330
    35x10=350
    350-330=20
    Mrs Barker need 10 bags and you will eat 20 candys.

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  8. 11x30=330
    35x10=350
    350-330=20
    Mrs Barker needs 10 bags and you will eat 20 candys.

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  9. Thank you to everyone who helped me to solve my problem. I am going to buy nine bags of candy this weekend for the party! I can't wait for Halloween.

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  10. you need 9 bags
    35+35+35+35+35+35+35+35+35=315
    minus 15 = 300 divided by 30 = 10
    you have 15 left over



    - VC

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  11. you need 9 bags so the kids will get 11 peices of candy each.



    leila

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